Humber/Ontario Real Estate Course 2 Exam Practice

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Question: 1 / 50

What is the total square footage of a square room with one side measuring 13 feet, a trapezoid room with parallel sides measuring 26 feet and 31 feet, and 16 feet between them, and a rectangular room measuring 21 feet long and 22 feet wide?

1,087 square feet

To find the total square footage of the rooms given, we need to calculate the area of each room separately and then add them together. 1. The square room has one side measuring 13 feet. The area of a square is calculated by multiplying the length of one side by itself (squared). So, for the square room: Area = \( 13 \text{ feet} \times 13 \text{ feet} = 169 \text{ square feet} \) 2. The trapezoid room has parallel sides measuring 26 feet and 31 feet, with a height of 16 feet between them. The formula for the area of a trapezoid is: Area = \( \dfrac{a + b}{2} \times h \), where \( a \) and \( b \) are the lengths of the parallel sides, and \( h \) is the height. Plugging in the values: Area = \( \dfrac{26 + 31}{2} \times 16 = 28.5 \times 16 = 456 \text{ square feet} \) 3. The rectangular room measures 21 feet long and 22 feet wide. The area of a rectangle is calculated by multiplying its length by its width. So, for the rectangular room: Area = \( 21 \text{ feet} \times 22 \text{ feet} = 462 \text{ square feet} \) Finally, adding the areas of all three rooms together: Total square footage = 169 square feet (square room) + 456 square feet (trapezoid room) + 462 square feet (rectangular room) = 1,087 square feet. Therefore, the correct answer is A. 1,087 square feet, as it represents the total square footage of all the rooms combined accurately.

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